1-1 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} 100 \ut{acre} &\le 1\ut{hide}\le120 \ut{acre}\\ 1\ut{acre} &= 4047\ut{m^2}\\ 1\ut{wapantake} &= 100\ut{hide}\\ 1\ut{barn} &= 1\times10 ^{-28}\ut{m^2}\\ \end{cases} $$ $$ 43\ut{wapentake}:8.0\ut{barn}=? $$ $$ \begin{aligned} &\min\(\frac{43\ut{wapantake}}{8.0\ut{barn}}\)\\ &= \frac{43\ut{wapantake}}{8.0\ut{barn}} \times\frac{100\ut{hide}}{1\ut{wapantake}}\times\frac{100\ut{acre}}{1\ut{hide}} \times\frac{4047\ut{m^2}}{1\ut{acre}} \times\frac{1\ut{barn}}{1\times10^{-28}\ut{m^2}}\\ &=\frac{43\times100\times100\times4047}{8\times10^{-28}}\\ &=2.1752625 \times 10^{36}\\ &\approx2 \times 10^{36}\\ \end{aligned} $$ $$ \begin{aligned} &\max\(\frac{43\ut{wapantake}}{8.0\ut{barn}}\)\\ &= \frac{43\ut{wapantake}}{8.0\ut{barn}} \times\frac{100\ut{hide}}{1\ut{wapantake}}\times\frac{120\ut{acre}}{1\ut{hide}} \times\frac{4047\ut{m^2}}{1\ut{acre}} \times\frac{1\ut{barn}}{1\times10^{-28}\ut{m^2}}\\ &=\frac{43\times100\times120\times4047}{8\times10^{-28}}\\ &=2.610315 \times 10^{36}\\ &\approx3 \times 10^{36}\\ \end{aligned} $$ $$2 \times 10^{36}:1 \lessapprox 43\ut{wapentake}:8.0\ut{barn}\lessapprox 3 \times 10^{36}:1 $$