10판/3. 벡터

3-35 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 8. 10. 20:09

{p:(3.50,220)q:(6.30,75.0)\begin{cases} \vec p:(3.50,220^\circ)\\ \vec q:(6.30,75.0^\circ)\\ \end{cases}
(a)p×q=?\vec p \times \vec q=? Ans=p×q=pqsinϕ=3.506.30sin(22075.0)12.7,z Direction \begin{aligned} \Ans =& \vec p \times \vec q\\ =&pq\sin\phi\\ =&3.50\cdot6.30\sin(220^\circ-75.0^\circ)\\ \approx&12.7 \, ,-z \text{ Direction} \end{aligned}
(b)pq=?\vec p \cdot \vec q=? Ans=pq=pqcosϕ=3.506.30cos(22075.0)18.1 \begin{aligned} \Ans =& \vec p \cdot \vec q\\ =&pq\cos\phi\\ =&3.50\cdot6.30\cos(220^\circ-75.0^\circ)\\ \approx&-18.1 \end{aligned}