3-34 할리데이 10판 솔루션 일반물리학

$$\begin{cases} \vec a= 3.0\hat i + 5.0\hat j\\ \vec b = 2.0\hat i + 4.0\hat j\\ \end{cases} $$
(a)$\vec a \times \vec b=?$ $$ \begin{aligned} \Ans =& \vec a \times \vec b\\ =& \begin{vmatrix} \hat i & \hat j & \hat k\\ 3.0 & 5.0 & 0\\ 2.0 & 4.0 & 0\\ \end{vmatrix}\\ =& \begin{vmatrix} 5.0 & 0 \\ 4.0 & 0 \\ \end{vmatrix} \hat i + \begin{vmatrix} 0 & 3.0 \\ 0 & 2.0 \\ \end{vmatrix} \hat j + \begin{vmatrix} 3.0 & 5.0 \\ 2.0 & 4.0 \\ \end{vmatrix} \hat k\\ =&(5.0\cdot0-0\cdot4.0)\hat i+(0\cdot2.0-3.0\cdot0)\hat j \\ &+(3.0\cdot4.0-5.0\cdot2.0)\hat k\\ =&2.0\hat k\\ \end{aligned} $$
(b)$\vec a \cdot \vec b=?$ $$ \begin{aligned} \Ans =& \vec a \cdot \vec b\\ =&3.0\cdot2.0+5.0\cdot4.0\\ =&26\\ \end{aligned} $$
(c)$(\vec a+ \vec b) \cdot \vec b=?$ $$ \begin{aligned} \Ans =& (\vec a+ \vec b) \cdot \vec b\\ =&(5.0\hat i+9\hat j)\cdot(2.0\hat i+4.0\hat j)\\ =&46\\ \end{aligned} $$
(d)$a\cos\phi=?$ $$ \begin{aligned} \Ans=&|\vec a|\cos\phi\\ =&\frac{\vec a \cdot \vec b}{|\vec b|}\\ =&\frac{26}{\sqrt{2^2+4^2}}\\ =&\frac{13}{\sqrt5}\\ \approx&5.8 \end{aligned} $$