1-2 할리데이 11판 솔루션 일반물리학 {Δx1=23[cm]Δy1=19[cm]Δx2=28[cm]ΣΔy=9.50[m] \begin{cases} \Delta x_1 &= 23\ut{cm}\\ \Delta y_1 &= 19\ut{cm}\\ \Delta x_2 &= 28\ut{cm}\\ \Sigma \Delta y &= 9.50\ut{m}\\ \end{cases} ⎩⎨⎧Δx1Δy1Δx2ΣΔy=23[cm]=19[cm]=28[cm]=9.50[m] ΣΔx2−ΣΔx1=? \Sigma \Delta x_2 - \Sigma \Delta x_1=? ΣΔx2−ΣΔx1=? N=ΣΔyΔy1=9.50[m]19[cm]=50 \begin{aligned} N &= \frac{\Sigma \Delta y}{\Delta y_1} \\ &= \frac{9.50\ut{m}}{19\ut{cm}}\\ &= 50 \end{aligned} N=Δy1ΣΔy=19[cm]9.50[m]=50 $$ \begin{aligned} \Ans&=\Sigma \Delta x_2 - \Sigma \Delta x_1\\ &= N \cdot \Delta x_2 - N .. 11판/1. 측정 2022.09.22
1-1 할리데이 11판 솔루션 일반물리학 {100[acre]≤1[hide]≤120[acre]1[acre]=4047[m2]1[wapantake]=100[hide]1[barn]=1×10−28[m2] \begin{cases} 100 \ut{acre} &\le 1\ut{hide}\le120 \ut{acre}\\ 1\ut{acre} &= 4047\ut{m^2}\\ 1\ut{wapantake} &= 100\ut{hide}\\ 1\ut{barn} &= 1\times10 ^{-28}\ut{m^2}\\ \end{cases} ⎩⎨⎧100[acre]1[acre]1[wapantake]1[barn]≤1[hide]≤120[acre]=4047[m2]=100[hide]=1×10−28[m2] 43[wapentake]:8.0[barn]=? 43\ut{wapentake}:8.0\ut{barn}=? 43[wapentake]:8.0[barn]=? $$ \begin{aligned} &\min\(\frac{43\ut{wapantake}}{8.0\ut{barn}}\)\\ &= \frac{43\ut{wapantake}}{8.0\ut{barn}} \times\frac{100\ut{hide}}{1\ut{wapantake}}\times\frac{100\ut{acre}}.. 11판/1. 측정 2022.09.22