11판/11. 굴림운동, 토크, 각운동량

11-57 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 6. 16. 18:05
{m=31[g]d=15[cm]ω=0.85[rad/s] \begin{cases} m&=31\ut{g}\\ d&=15\ut{cm}\\ \omega &= 0.85\ut{rad/s}\\ \end{cases} (a)\ab{a} ΣI=IA+IB+IC=mRA2+mRB2+mRC2=m{d2+(2d)2+(3d)2}=14md2=9.765×103[kgm2]9.8×103[kgm2]9.8[gm2] \begin{aligned} \Sigma I &=I_A+I_B+I_C\\ &=m{R_A}^2+m{R_B}^2+m{R_C}^2\\ &=m\bra{{d}^2+\br{2d}^2+\br{3d}^2}\\ &=14md^2\\ &=9.765\times10^{-3}\ut{kg\cdot m^2}\\ &\approx 9.8\times10^{-3}\ut{kg\cdot m^2}\\ &\approx 9.8\ut{g\cdot m^2}\\ \end{aligned} (b)\ab{b} L=Iω,L = I\omega, LB=IBω=m(2d)2ω=4md2ω=15.81×103[kgm2/s]16×103[kgm2/s]16[gm2/s] \begin{aligned} L_B &= I_B\omega\\ &= m\br{2d}^2\omega\\ &= 4md^2\omega\\ &=15.81\times10^{-3}\ut{kg\cdot m^2/s}\\ &\approx 16\times10^{-3}\ut{kg\cdot m^2/s}\\ &\approx 16\ut{g\cdot m^2/s}\\ \end{aligned} (c)\ab{c} L=Iω,L = I\omega, ΣL=Σ(Iω)=ωΣI=ω(14md2)=14md2ω=55.335×103[kgm2/s]55×103[kgm2/s]55[gm2/s] \begin{aligned} \Sigma L &=\Sigma \br{I\omega}\\ &=\omega\Sigma {I}\\ &=\omega\br{14md^2}\\ &=14md^2\omega\\ &=55.335\times 10^{-3}\ut{kg\cdot m^2/s}\\ &\approx 55\times 10^{-3}\ut{kg\cdot m^2/s}\\ &\approx 55\ut{g\cdot m^2/s}\\ \end{aligned}