11-16 할리데이 11판 솔루션 일반물리학

$$\begin{cases} \vec \tau_1&=3.8\i\ut{N\cdot m}\\ \vec \tau_2&=-4.6\j\ut{N\cdot m}\\ \end{cases}$$ $$\begin{aligned} \dyt{\vec L}&=\tau_\net\\ &=\tau_1+\tau_2\\ &=3.8\i-4.6\j\ut{N\cdot m}\\ \end{aligned}$$