10-24 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} m&=30\ut{kg}\\ R&=0.50\ut{m}\\ r&=0.20\ut{m}\\ F&=140\ut{N}\\ a&=0.80\ut{m/s^2}\\ g&=9.80665\ut{m/s^2} \end{cases} $$ $$ \begin{cases} \Sigma F&=ma\\ \Sigma \tau&=I\alpha\\ a&=r\alpha\\ \end{cases} $$ $$ \begin{cases} T-mg&=ma\\ FR-Tr&=I\alpha\\ a&=r\alpha\\ \end{cases} $$ $$ \begin{aligned} I&=\frac{r }{a}\bra{F R-m r (a+g)}\\ &=\frac{163}{10}-\frac{3 g}{2}\\ &=1.590025\ut{kg\cdot m^2}\\ &\approx 1.6\ut{kg\cdot m^2}\\ \end{aligned} $$