11판/8. 퍼텐셜에너지와 에너지 보존

8-3 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 3. 26. 19:07
$$ \begin{cases} P&=92\ut{MW}\\ v&=32.5\ut{knot}\\ 1\ut{knot}&=1.852\ut{km/h}=\frac{463}{900}\ut{m/s}\\ \end{cases} $$ $$P=\vec F\cdot \vec v,$$ $$ \begin{aligned} F&=\frac{P}{v}\\ &=\frac{92\ut{MW}}{32.5\ut{knot}}\cdot\frac{1\ut{knot}}{\frac{463}{900}\ut{m/s}}\\ &=\frac{33120}{6019}\ut{MN}\\ &\approx 5.502575178601097\ut{MN}\\ &\approx 5.5\ut{MN}\\ \end{aligned} $$