1-12 할리데이 10판 솔루션 일반물리학

$$ \begin{aligned} & 10^{10}\ut{years} : 10^6\ut{years} = 1.0\ut{days} : x\ut{s} \end{aligned} $$ $$ \begin{aligned} \\ x &= \frac{10^6\ut{years} \times 1.0\ut{days}}{10^{10}\ut{years}} \\ &= \frac{10^6\ut{years} \times 1.0\ut{days}}{10^{10}\ut{years}} \times \frac{24\ut{h}}{1\ut{days}} \times \frac{3600\ut{s}}{1\ut{h}} \\ &= \frac{10^6 \times 1\times 24\times 3600}{10^{10}\times 1\times 1}\ut{s} \\ &= \frac{216}{25}\ut{s} \\ &= 8.64\ut{s} \end{aligned} $$