1-11 할리데이 10판 솔루션 일반물리학

$$ \begin{aligned} & 100.0\ut{years} : \pm0.010\ut{s} = 1.0\ut{s} : \pm x\ut{s} \end{aligned} $$ $$ \begin{aligned} \\ x &= \frac{0.010\ut{s} \cdot 1.0\ut{s}}{100.0\ut{years}} \\ &= \frac{0.010\ut{s} \cdot 1.0\ut{s}}{100.0\ut{years}}\cdot \frac{1\ut{years}}{365.2422\ut{days}} \cdot \frac{1\ut{days}}{24\ut{h}}\cdot \frac{1\ut{h}}{3600\ut{s}} \\ &= \frac{0.010 \cdot 1.0\cdot 1\cdot 1\cdot 1}{100.0 \cdot 365.2422 \cdot 24 \cdot 3600}\ut{s} \\ &= \frac{1}{315569260800}\ut{s} \\ &\approx 3.168876453507857\times10^{-12}\ut{s} \\ &\approx 3.2\times10^{-12}\ut{s} \end{aligned} $$ $$ \begin{aligned} \\ \therefore \Ans &= 1.0\pm3.2\times10^{-12}\ut{s} \\ &= 1.0\ut{s} \pm 3.2\ut{ps} \end{aligned} $$