5-38 할리데이 11판 솔루션 일반물리학

$$\begin{cases} m_1&=2.95\ut{kg}\\ m_2&=2.40\ut{kg}\\ \theta&=30.0\degree \end{cases}$$ $$\Sigma \vec F = m\vec a,$$ $$\begin{cases} \Sigma F_1 &= m_1 a\\ \Sigma F_2 &= m_2 a\\ \end{cases}$$ $$\begin{cases} m_1g\sin\theta-T &= m_1 a\\ T-m_2g &= m_2 a\\ \end{cases}$$ $$\ab{a}$$ $$\begin{aligned} a &= a_1= a_2 \\ &=-\frac{37g}{214}\\ &\approx -1.695542289719626\ut{m/s^2}\\ &\approx -1.70\ut{m/s^2}\\ \end{aligned}$$ $$\ab{b}$$ $$y-$$ $$\ab{c}$$ $$\begin{aligned} T &= \frac{1062g}{535}\\ &\approx 19.4666585046729\ut{N}\\ &\approx 19.5\ut{N}\\ \end{aligned}$$