5-32 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} F&=4.0\times10^5\ut{N}\\ m&=3.8\times10^4\ut{kg} \end{cases} $$ $$\Sigma \vec F = m\vec a,$$ $$ \begin{aligned} F-mg&=ma\\ \end{aligned} $$ $$ \begin{aligned} a&=\frac{F-mg}{m}\\ &=\frac{F}{m}-g\\ &=\frac{200}{19}-g\\ &\approx 0.7196657894736855\ut{m/s^2}\\ &\approx 0.72\ut{m/s^2} \end{aligned} $$