5-9 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} m_1 &= 1.15\ut{kg}\\ m_2 &= 3.30\ut{kg}\\ g&=9.80665\ut{m/s^2}\\ \end{cases} $$ $$\Sigma \vec F = m\vec a,$$ $$ \begin{cases} \Sigma \vec F_1 &= m_1\vec a\\ \Sigma \vec F_2 &= m_2\vec a\\ \end{cases} $$ $$ \begin{cases} T-m_1g &= m_1a\\ -T+m_2g &= m_2a\\ \end{cases} $$ $$ \begin{cases} a&=\cfrac{43g}{89}\\ T&=\cfrac{759g}{445}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} a&=\frac{43g}{89}\\ &\approx 4.738044382022472\ut{m/s^2}\\ &\approx 4.74\ut{m/s^2}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} T&=\frac{759g}{445}\\ &\approx 16.72639853932584\ut{N}\\ &\approx 16.7\ut{N}\\ \end{aligned} $$