4-11 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} v_x &= 15.0\ut{m/s}\\ t&=0.140\ut{s}\\ g&=9.80665\ut{m/s^2} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} S&=v_0t+\frac{1}{2}at^2\\ -\Delta y&=(0)t+\frac{1}{2}(-g)(0.14)^2\\ \Delta y&=0.09610517\ut{m}\\ &= 9.610517\ut{cm}\\ &\approx 9.61\ut{cm}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \Delta x &= v_x t\\ &=15.0\ut{m/s}\cdot0.140\ut{s}\\ &= 2.1\ut{m} &= 2.10\ut{m} \end{aligned} $$