4-29 할리데이 10판 솔루션 일반물리학

$$\begin{cases} v_0 &= 6.00v_{H}\\ \vec a &= -g\j\\ \end{cases}$$ $$\theta_0=?$$ $$\begin{aligned} \vec v_H &= \vec v_x,\\ \end{aligned}$$ $$\begin{aligned} \theta_0&=\cos^{-1}\frac{v_x}{v_0}\\ &=\cos^{-1}\frac{v_H}{6v_H}\\ &=\cos^{-1}\frac{1}{6}\\ &\approx 1.40334824758\ut{rad}\\ &\approx 1.40\ut{rad}\\ \end{aligned}$$