10판/3. 벡터

3-10 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 8. 6. 18:36

{c=(7.4)i^+(3.8)j^+(6.1)k^d=(4.4)i^+(2.0)j^+(3.3)k^\begin{cases} \vec c = \(7.4 \)\hat i + \(-3.8 \)\hat j + \(-6.1 \)\hat k\\ \vec d = \(4.4 \)\hat i + \(-2.0 \)\hat j + \(3.3 \)\hat k\\ \end{cases} r=(7.4+4.4)i^+(3.82.0)j^+(6.1+3.3)k^=(11.8)i^+(5.8)j^+(2.8)k^ \begin{aligned} \vec r &= \(7.4+4.4 \)\hat i + \(-3.8-2.0 \)\hat j + \(-6.1+3.3 \)\hat k\\ &=\(11.8 \)\hat i + \(-5.8 \)\hat j + \(-2.8 \)\hat k \end{aligned}
(a)rx=11.8r_x=11.8
(b)ry=5.8r_y=-5.8
(c)rz=2.8r_z=-2.8