10-52 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \Delta t&=220\ut{ms}=0.220\ut{s}\\ \omega_i&=0\\ \omega_f&=7.00\ut{rad/s}\\ I&=16.0\ut{kg\cdot m^2}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \bar\alpha&=\frac{\Delta \omega}{\Delta t}\\ &=\frac{350}{11}\ut{rad/s^2}\\ &\approx 31.818181818181817\ut{rad/s^2}\\ &\approx 31.8\ut{rad/s^2}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \bar\tau &= I \alpha\\ &=\frac{5600}{11}\ut{N\cdot m}\\ &\approx 509.09090909090907\ut{N\cdot m}\\ &\approx 509\ut{N\cdot m}\\ \end{aligned} $$