1-23 할리데이 10판 솔루션 일반물리학

$$ \begin{cases} S &= 6.00\ut{m^2} \\ m &= 324\ut{kg} \\ \rho &= 2.70 \times 10^3 \ut{kg/m^3} \end{cases} $$ d=? $$ \begin{aligned} \\ \Ans &= d = \frac{Volume}{Area} \\ &= \frac{m}{\rho \cdot S} \\ &= \frac{324\ut{kg}}{2.70 \times 10^3\ut{kg/m^3} \cdot 6.00\ut{m^2}} \\ &= \frac{1}{50}\ut{m} \\ &= 0.02\ut{m} = 2.00\ut{cm} \end{aligned} $$