4-65 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \vec v_0&=5.02\i-9.24\j\ut{m/s}\\ \Delta t &= 3.00\ut{s}\\ \vec v_1&=0 \end{cases} $$ $$ \begin{aligned} \vec a &= \frac{\Delta \vec v}{\Delta t}\\ &= \frac{\vec v_1-\vec v_0}{\Delta t}\\ &= \frac{\vec v_1}{\Delta t}\\ &= \frac{5.02\i-9.24\j}{3}\ut{m/s^2}\\ &= \frac{251}{150}\i-\frac{77}{25}\j\ut{m/s^2}\\ &\approx 1.67\i-3.08\j\ut{m/s^2} \end{aligned} $$