11판/3. 벡터

3-42 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 1. 25. 17:20
{d=1.5[m]j^ \begin{cases} \vec d &=-1.5\ut{m}\j \end{cases} (a)\ab{a} 6.0d=9j^=9 \begin{aligned} \abs{6.0\vec d} &= \abs{-9\j}\\ &=9 \end{aligned} (b)\ab{b} South\text{South} (c)\ab{c} 2.0d=3j^=3 \begin{aligned} \abs{-2.0\vec d} &= \abs{3\j}\\ &=3 \end{aligned} (b)\ab{b} North\text{North}