11판/2. 직선운동

2-57 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 1. 18. 18:06
{S=1.20[m]v1=530[m/s] \begin{cases} S&=1.20\ut{m}\\ v_1&=530\ut{m/s}\\ \end{cases} S=12(v+v0)t,1.2=12(530+0)t \begin{aligned} S&=\frac{1}{2}(v+v_0)t,\\ 1.2&=\frac{1}{2}(530+0)t\\ \end{aligned} t=61325[s]0.004528301886792453[s]4.54×103[s]4.54[ms] \begin{aligned} t&=\frac{6}{1325}\ut{s}\\ &\approx 0.004528301886792453\ut{s}\\ &\approx 4.54\times10^{-3}\ut{s}\\ &\approx 4.54\ut{ms}\\ \end{aligned}