1-16 할리데이 11판 솔루션 일반물리학

$$\begin{cases} 1\ut{ha}&=10^4\ut{m^2}\\ \end{cases}$$ $$\begin{aligned} V&=57\ut{ha}\times17\ut{m}\\ &=57\ut{ha}\times\frac{10^4\ut{m^2}}{1\ut{ha}}\times17\ut{m}\\ &=969\times10^4\ut{m^3}\\ &=969\times10^4\ut{m^3}\times\(\frac{1\ut{km}}{10^3\ut{m}}\)^3\\ &=9.69\times10^{-3}\ut{km^3}\\ \end{aligned}$$