11판/1. 측정

1-12 할리데이 11판 솔루션 일반물리학

짱세디럭스 2022. 9. 30. 04:55

ρ=1[g/cm3] \rho = 1\ut{g/cm^3} (a) \ab{a} m=ρV=1[g/cm3]1[m3]=1[g]1[cm3]1[kg]1000[g](100[cm]1[m])31[m3]=10031000[kg]=1000[kg] \begin{aligned} m &= \rho V\\ &= 1\ut{g/cm^3} \cdot 1\ut{m^3}\\ &= \cfrac{1\ut{g}}{1\ut{cm^3}} \cdot \cfrac{1\ut{kg}}{1000\ut{g}}\cdot\(\cfrac{100\ut{cm}}{1\ut{m}}\)^3\cdot 1\ut{m^3} \\ &=\cfrac{100^3}{1000}\ut{kg}\\ &=1000\ut{kg} \end{aligned} (b) \ab{b} Ans=4800[m3]15.7[h]1000[kg]1[m3]1[h]3600[sec]=4800100015.73600[kg/s]=40000471[kg/s]84.9256900212[kg/s]84.9[kg/s]85[kg/s] \begin{aligned} \Ans&=\cfrac{4800\ut{m^3}}{15.7\ut{h}}\cdot\cfrac{1000\ut{kg}}{1\ut{m^3}}\cdot\cfrac{1\ut{h}}{3600\ut{sec}}\\ &=\cfrac{4800\cdot1000}{15.7\cdot3600}\ut{kg/s}\\ &=\cfrac{40000}{471}\ut{kg/s}\\ &\approx84.9256900212\ut{kg/s}\\ &\approx84.9\ut{kg/s}\\ &\approx85\ut{kg/s}\\ \end{aligned}

풀이자주 : (b)의 유효숫자가 모호하여 다양하게 표기했습니다.