$$ \begin{cases} m&=2.0\ut{kg}\\r&=2.0\ut{m},\theta_r=45\degree\\v&=4.0\ut{m/s},\theta_2=30\degree\\F&=2.0\ut{N},\theta_3=30\degree\\\end{cases} $$$$ \begin{aligned}\vec r&=r\cos\theta_r\i+r\sin\theta_r\j\\&=\sqrt2\i+\sqrt2\j\taag1\\\end{aligned} $$$$\theta_v=\theta_r-180\degree-\theta_2,$$$$ \begin{aligned}\vec v&=v\cos\theta_v\i+r\sin\theta_v\j\\&=-(\sqrt6+\sqrt2)\i-(\sqrt6-\sqrt2)\j\taag2\\\e..