솔루션피아

$$ \begin{cases} H &= 145\ut{m}\\ h&=H-2R=144\ut{m}\\ g &= 9.80665\ut{m/s^2} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} S&=v_0t+\frac{1}{2}at^2,\\ -h&=(0)t+\frac{1}{2}(-g)t^2\\ -144&=\frac{1}{2}(-g)t^2\\ \end{aligned} $$ $$ \begin{aligned} t&=\frac{2400}{\sqrt{196133}}\ut{s}\\ &\approx 5.41920906902145\ut{s}\\ &\approx 5.42\ut{s}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} 2aS&=v^2-v_0^2,..

$$ \begin{cases} \Delta x &= 20.0\ut{m}\\ v_0&=70.0\ut{km/h}=\cfrac{175}{9}\ut{m/s}\\ t&=1.20\ut{s} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} S&=v_0t+\frac{1}{2}at^2,\\ 20&=\(\frac{175}{9}\)(1.20)+\frac{1}{2}a(1.20)^2 \end{aligned} $$ $$ \begin{aligned} a&=-\frac{125}{27}\ut{m/s^2}\\ \Ans&=\abs{a}=\frac{125}{27}\ut{m/s^2}\\ &\approx4.62962962962963\ut{m/s^2}\\ &\approx4.63\ut{m/s^2}\\ \end{al..

$$ \begin{cases} x&=20te^{-2t}\ut{m} \end{cases} $$ $$ \begin{aligned} v&=\dxt{x}=\dt\(20te^{-2t}\)\\ &=20e^{-2t}(1-2t)=0\\ \end{aligned} $$ $$\therefore t=\frac{1}{2}\ut{s}$$ $$ \begin{aligned} x(t)&=20te^{-2t}\ut{m},\\ \Ans&=x\(\frac{1}{2}\)\\ &=\frac{10}{e}\ut{m}\\ &\approx3.678794411714423\ut{m}\\ &\approx3.7\ut{m}\\ \end{aligned} $$

$$ \begin{cases} v_0&=16\ut{m/s}\\ t&=2.4\ut{s}\\ v_1&=-28\ut{m/s} \end{cases} $$ $$ \begin{aligned} v&=v_0+at,\\ -28&=16+a(2.4)\\ \end{aligned} $$ $$ \begin{aligned} a&=-\frac{55}{3}\ut{m/s^2}\\ &\approx-18.33333333333333\ut{m/s^2}\\ &\approx-18\ut{m/s^2}\\ \end{aligned} $$

$$\ab{a}$$ $$ \begin{aligned} v&=v_0+at,\\ 3.0\times10^8\cdot\frac{0.1}{100}&=0+(9.8)t\\ \end{aligned} $$ $$ \begin{aligned} t&=\frac{1500000}{49}\ut{s}\\ &=\frac{25000}{49}\ut{min}\\ &=\frac{1250}{147}\ut{h}\\ &=8\ut{h}+30\ut{min}+\frac{600}{49}\ut{s}\\ &\approx8\ut{h}+30\ut{min}+12.24489795918367\ut{s}\\ &\approx8\ut{h}+30\ut{min}+12\ut{s}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} S&=v_..

$$ \begin{aligned} \Ans&=\Delta x\\ &=\int_0^{16}v\dd t\\ &=\frac{1}{2}\cdot2\cdot12+8\cdot12+\frac{1}{2}\cdot(6+12)\cdot2+4\cdot6\\ &=150\ut{m} \end{aligned} $$

$$ \begin{cases} v&=18.0\ut{m/s}\\ H&=90.0\ut{m} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} S&=v_0t+\frac{1}{2}at^2,\\ -H&=(18)t+\frac{1}{2}(-g)t^2\\ \end{aligned} $$ $$ \begin{aligned} t&=\frac{600 }{196133}\left(600+\sqrt{2321330}\right)\ut{s}\\ &\approx 6.496380983846016 \ut{s}\\ &\approx 6.50 \ut{s}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} 2aS&=v^2-v_0^2,\\ 2(-g)(-H)&=v^2-(18.0)^2\..

$$ \begin{cases} d&=20.0\ut{m}\\ v_p&=14.0\ut{m/s}\\ D_{23}&=200\ut{m}\\ D_{12}&=300\ut{m} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \Delta t &= \frac{d}{v}\\ &=\frac{20.0\ut{m}}{14.0\ut{m/s}}\\ &=\frac{10}{7}\ut{s}\\ &\approx1.428571428571429\ut{s}\\ &\approx1.43\ut{s} \end{aligned} $$ $$\ab{b}$$ $$ \begin{cases} t_r&=0.500\ut{s}\\ a&=5.00\ut{m/s^2}\\ v_0&=0\\ t_\Ans &=t_r+\Delta t\\ S&=D_{1..

$$ \begin{cases} \text{A : in Air}\\ \text{B : in Water}\\ \end{cases} $$ $$ \begin{cases} H_A&=7.00\ut{m}\\ t_B&=4.00\ut{s}\\ g&=9.80665\ut{m/s^2} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} 2aS&=v^2-v_0^2,\\ 2(-g)(-H)&=v^2-(0)^2 \end{aligned} $$ $$ \begin{aligned} v_B&=\sqrt{2gH}\\ &=\sqrt{14g} \end{aligned} $$ $$ \begin{aligned} H_B&=v_B\cdot t\\ &=\(\sqrt{14g}\)\cdot (4\ut{s})\\ &=\frac{7}{..

12-23 할리데이 11판 솔루션 일반물리학$$ \begin{cases} \text{A : Car}\\ \text{B : Truck} \end{cases} $$ $$ \begin{cases} a_A&=1.80\ut{m/s^2}\\ v_{A0}&=0\\ v_B&=7.30\ut{m/s} \end{cases} $$ $$\ab{a}$$ $$S=v_0t+\frac{1}{2}at^2,$$ $$ \begin{aligned} S&=v_0t+\frac{1}{2}at^2\\ v_Bt&=(0)t+\frac{1}{2}(a_A)t^2\\ \(7.30\ut{m/s}\)&=\frac{1}{2}\(1.80\ut{m/s^2}\)t\\ \end{aligned} $$ $$ t=\frac{73}{9}\ut{s} $$ $$ \begin{al..