10-5 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} v_B&=114\ut{km/h}=\frac{95}{3}\ut{m/s}\\ r_A&=92\ut{m}\\ r_B&=100\ut{m}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \omega&=\frac{v}{r}\\ &=\frac{19}{60}\ut{rad/s}\\ &\approx 0.31666666666666665\ut{rad/s}\\ &\approx 0.32\ut{rad/s}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} v&=r\omega\\ &=\frac{437}{15}\ut{m/s}\\ &~~~~~\approx 29.133333333333333\ut{m/s}\\ &~~~~~\approx 29\ut{m/s}\\ &=\frac{2622}{25}\ut{km/h}\\ &~~~~~=104.88\ut{km/h}\\ &~~~~~\approx 105\ut{km/h}\\ \end{aligned} $$